[Slackers] lda followup

[Steve Judd]

Jaymz,

Looks like Sirius appies > and < correctly, i.e. as a modifier to the #
character.  Thus

	lda #>blah+1

is the same as

	lda #>(blah+1)

Moreover,

	lda #1+>blah

will generate an error.  From the WDC 65816 data sheet:

7.3.3.4 The assembler shall use the <, >, and ^ characters after the #
character in immediate address to specify which byte or bytes will be
selected from the value of the operand.  Any calculations in the operand
must be performed before the byte selection takes place. ...

-S